Hi,
I did it, because that's the way to get the correct address.
Please note that the address field consists of bits [31:2] of DW2. Bits 1 and 0 of DW2 are reserved, and must be zero. So in effect, DW2 is the used bus address in that example, which is forced to be DW aligned.
But who knows, maybe bit 1 and 0 will be used for something else in future specs. So we consider bits [31:2] and multiply by four.
I hope this clarified this issue.
Regards,
Eli